1) Display the details of all employees
SQL>Select * from emp;
2) Display the depart information from department table
SQL>select * from dept;
3) Display the name and job for all theemployees
SQL>select ename,job from emp;
4) Display the name and salary for all the employees
SQL>select ename,sal from emp;
5) Display the employee no and totalsalary for all the employees
SQL>select empno,ename,sal,comm, sal+nvl(comm,0) as”total salary” from emp;
6) Display the employee name and annual salary for all employees.
SQL>select ename, 12*(sal+nvl(comm,0)) as “annual Sal” from emp;
7) Display the names of all the employees who are working in depart number 10.
SQL>select emame from emp where deptno=10;
8 ) Display the names of all the employees who are working as clerks and drawing a salary more than 3000.
SQL>select ename from emp where job=’CLERK’ and sal>3000;
9) Display the employee number and name who are earning comm.
SQL>select empno,ename from emp where comm is not null;
10) Display the employee number and name who do not earn any comm.
SQL>select empno,ename from emp where comm is null;
11) Display the names of employees who are working as clerks,salesman or analyst and drawing a salary more than 3000.
SQL>select ename from emp where job=’CLERK’ OR JOB=’SALESMAN’ OR JOB=’ANALYST’ AND SAL>3000;
12) Display the names of the employees who are working in the company for the past 5 years;
SQL>select ename from emp where to_char(sysdate,’YYYY’)-to_char(hiredate,’YYYY’)>=5;
13) Display the list of employees who have joined the company before 30-JUN-90 or after 31-DEC-90.
SQl> select ename from emp where hiredate < ’30-JUN-1990′ or hiredate >’31-DEC-90′;
14) Display current Date.
SQL>select sysdate from dual;
15) Display the list of all users in your database(use catalog table).
SQL>select username from all_users;
16) Display the names of all tables from current user;
SQL>select tname from tab;
17) Display the name of the current user.
SQL>show user;
18) Display the names of employees working in depart number 10 or 20 or 40 or employees working asCLERKS,SALESMAN or ANALYST.
SQL>select ename from emp where deptno in(10,20,40) or job in(‘CLERKS’,'SALESMAN’,'ANALYST’);
19) Display the names of employees whose name starts with alaphabet S.
SQL>select ename from emp where ename like ‘S%’;
20) Display the Employee names for employees whose name ends with alaphabet S.
SQL>select ename from emp where ename like ‘%S’;
21) Display the names of employees whose names have second alphabet A in their names.
SQL>select ename from emp where ename like ‘_A%’;
22) select the names of the employee whose names is exactly five characters in length.
SQL>select ename from emp where length(ename)=5;
23) Display the names of the employee who are not working as MANAGERS.
SQL>select ename from emp where job not in(‘MANAGER’);
24) Display the names of the employee who are not working as SALESMAN OR CLERK OR ANALYST.
SQL>select ename from emp where job not in(‘SALESMAN’,'CLERK’,'ANALYST’);
25) Display all rows from emp table.The system should wait after every screen full of informaction.
SQL>set pause on;
26) Display the total number of employee working in the company.
SQL>select count(*) from emp;
27) Display the total salary beiging paid to all employees.
SQL>select sum(sal) from emp;
28) Display the maximum salary from emp table.
SQL>select max(sal) from emp;
29) Display the minimum salary from emp table.
SQL>select min(sal) from emp;
30) Display the average salary from emp table.
SQL>select avg(sal) from emp;
31) Display the maximum salary being paid to CLERK.
SQL>select max(sal) from emp where job=’CLERK’;
32) Display the maximum salary being paid to depart number 20.
SQL>select max(sal) from emp where deptno=20;
33) Display the minimum salary being paid to any SALESMAN.
SQL>select min(sal) from emp where job=’SALESMAN’;
34) Display the average salary drawn by MANAGERS.
SQL>select avg(sal) from emp where job=’MANAGER’;
35) Display the total salary drawn by ANALYST working in depart number 40.
SQL>select sum(sal) from emp where job=’ANALYST’ and deptno=40;
36) Display the names of the employee in order of salary i.e the name of the employee earning lowest salary should salary appear first.
SQL>select ename from emp order by sal;
37) Display the names of the employee in descending order of salary.
SQL>select ename from emp order by sal desc;
38) Display the names of the employee in order of employee name.
SQL>select ename from emp order by ename;
39) Display empno,ename,deptno,sal sort the output first base on name and within name by deptno and with in deptno by sal.
SQL>select empno,ename,deptno,sal from emp order by;
40) Display the name of the employee along with their annual salary(sal*12).The name of the employee earning highest annual salary should apper first.
SQL>select ename,sal*12 from emp order by sal desc;
41) Display name,salary,hra,pf,da,total salary for each employee. The output should be in the order of total salary,hra 15% of salary,da 10% of salary,pf 5% salary,total salary will be(salary+hra+da)-pf.
SQL>select ename,sal,sal/100*15 as hra,sal/100*5 as pf,sal/100*10 as da, sal+sal/100*15+sal/100*10-sal/100*5 as total from emp;
42) Display depart numbers and total number of employees working in each department.
SQL>select deptno,count(deptno)from emp group by deptno;
43) Display the various jobs and total number of employees within each job group.
SQL>select job,count(job)from emp group by job;
44) Display the depart numbers and total salary for each department.
SQL>select deptno,sum(sal) from emp group by deptno;
45) Display the depart numbers and max salary for each department.
SQL>select deptno,max(sal) from emp group by deptno;
46) Display the various jobs and total salary for each job
SQL>select job,sum(sal) from emp group by job;
47) Display the various jobs and total salary for each job
SQL>select job,min(sal) from emp group by job;
48) Display the depart numbers with more than three employees in each dept.
SQL>select deptno,count(deptno) from emp group by deptno having count(*)>3;
49) Display the various jobs along with total salary for each of the jobs where total salary is greater than 40000.
SQL>select job,sum(sal) from emp group by job having sum(sal)>40000;
50) Display the various jobs along with total number of employees in each job.The output should contain only those jobs with more than three employees.
SQL>select job,count(empno) from emp group by job having count(job)>3;
51) Display the name of the empployee who earns highest salary.
SQL>select ename from emp where sal=(select max(sal) from emp);
52) Display the employee number and name for employee working as clerk and earning highest salary among clerks.
SQL>select empno,ename from emp where where job=’CLERK’ and sal=(select max(sal) from emp where job=’CLERK’);
53) Display the names of salesman who earns a salary more than the highest salary of any clerk.
SQL>select ename,sal from emp where job=’SALESMAN’ and sal>(select max(sal) from emp where job=’CLERK’);
54) Display the names of clerks who earn a salary more than the lowest salary of any salesman.
SQL>select ename from emp where job=’CLERK’ and sal>(select min(sal) from emp where job=’SALESMAN’);
55) Display the names of the employees who earn highest salary in their respective departments.
SQL>select ename,sal,deptno from emp where sal in(select max(sal) from emp group by deptno);
56) Display the names of the employees who earn highest salaries in their respective job groups.
SQL>select ename,sal,job from emp where sal in(select max(sal) from emp group by job);
57) Display the employee names who are working in accounting department.
SQL>select ename from emp where deptno=(select deptno from dept wheredname=’ACCOUNTING’);
58) Display the employee names who are working in Ahmedabad .
SQL>select ename from emp where deptno=(select deptno from dept where LOC=’Ahmedabad’);
59) Display the Job groups having total salary greater than the maximum salary for managers.
SQL>SELECT JOB,SUM(SAL) FROM EMP GROUP BY JOB HAVING SUM(SAL)>(SELECT MAX(SAL) FROM EMP WHERE JOB=’MANAGER’);
60) Display the names of employees from department number 10 with salary grether than that of any employee working in other department.
SQL>select ename from emp where deptno=10 and sal>any(select sal from emp where deptno not in 10);
61) Display the names of the employees from department number 10 with salary greater than that of all employee working in other departments.
SQL>select ename from emp where deptno=10 and sal>all(select sal from emp where deptno not in 10);
62) Display the names of the employees in Uppercase.
SQL>select upper(ename)from emp;
63) Display the names of the employees in Lowecase.
SQL>select lower(ename)from emp;
64) Display the names of the employees in Propercase.
SQL>select initcap(ename)from emp;
65) Display the length of Your name using appropriate function.
SQL>select length(‘name’) from dual;
66) Display the length of all the employee names.
SQL>select length(ename) from emp;
67) select name of the employee concatenate with employee number.
SQL>select ename||empno from emp;
68) User appropriate function and extract 3 characters starting from 2 characters from the following string ‘Oracle’. i.e the out put should be ‘ac’.
SQL>select substr(‘oracle’,3,2) from dual;
69) Find the First occurance of character ‘a’ from the following string i.e ‘Computer Maintenance Corporation’.
SQL>SELECT INSTR(‘Computer Maintenance Corporation’,'a’,1) FROM DUAL;
70) Replace every occurance of alphabhet A with B in the string Allens(use translate function)
SQL>select translate(‘Allens’,'A’,'B’) from dual;
71) Display the informaction from emp table.Where job manager is found it should be displayed as boos(Use replace function).
SQL>select replace(JOB,’MANAGER’,'BOSS’) FROM EMP;
72) Display empno,ename,deptno from emp table.Instead of display department numbers display the related department name(Use decode function).
SQL>select empno,ename,decode(deptno,10,’ACCOUNTING’,20,’RESEARCH’,30,’SALES’,40,’OPRATIONS’) from emp;
73) Display your age in days.
SQL>select to_date(sysdate)-to_date(’10-sep-77′)from dual;
74) Display your age in months.
SQL>select months_between(sysdate,’10-sep-77′) from dual;
75) Display the current date as 15th Augest Friday Nineteen Ninety Saven.
SQL>select to_char(sysdate,’ddth Month day year’) from dual;
76) Display the following output for each row from emp table. A has joined the company on wednesday 13th August ninten nintey.
SQL>select ENAME||’ HAS JOINED THE COMPANY ON ‘||to_char(HIREDATE,’day ddth Month year’) from EMP;
77) Find the date for nearest saturday after current date.
SQL>SELECT NEXT_DAY(SYSDATE,’SATURDAY’)FROM DUAL;
78) Display current time.
SQL>select to_char(sysdate,’hh:MM:ss’) from dual.
79) Display the date three months Before the current date.
SQL>select add_months(sysdate,3) from dual;
80) Display the common jobs from department number 10 and 20.
SQL>select job from emp where deptno=10 and job in(select job from emp where deptno=20);
81)Display the names of employees who earn a salary more than that of A or that of salary grether than that of B.
SQL>select ename,sal from emp where sal> (select sal from emp where ename=’A')and sal> (select sal from emp where ename=’B');
81) Display the jobs found in department 10 and 20 Eliminate duplicate jobs.
SQL>select distinct(job) from emp where deptno=10 or deptno=20;
(or)
SQL>select distinct(job) from emp where deptno in(10,20);
82) Display the jobs which are unique to department 10.
SQL>select distinct(job) from emp where deptno=10;
83) Display the details of those who do not have any person working under them.
SQL>select e.ename from emp,emp e where emp.mgr=e.empno group by e.ename havingcount(*)=1;
84) Display the details of those employees who are in sales department and grade is 3.
SQL>select * from emp where deptno=(select deptno from dept where dname=’SALES’)and sal between(select losal from salgrade where grade=3)and (select hisal from salgrade where grade=3);
85) Display those who are not managers and who are managers any one.
i)display the managers names
SQL>select distinct(m.ename) from emp e,emp m where m.empno=e.mgr;
ii)display the who are not managers
SQL>select ename from emp where ename not in(select distinct(m.ename) from emp e,emp m where m.empno=e.mgr);
86) Display those employee whose name contains not less than 4 characters.
SQL>select ename from emp where length(ename)>4;
87) Display those department whose name start with “S” while the location name ends with “K”.
SQL>select dname from dept where dname like ‘S%’ and loc like ‘%K’;
88) Display those employees whose manager name is akash.
SQL>select p.ename from emp e,emp p where e.empno=p.mgr and e.ename=’Akash’;
89) Display those employees whose salary is more than 3000 after giving 20% increment.
SQL>select ename,sal from emp where (sal+sal*.2)>3000;
90) Display all employees while their dept names;
SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno;
91) Display ename who are working in sales dept.
SQL>select ename from emp where deptno=(select deptno from dept where dname=’SALES’);
92) Display employee name,deptname,salary and comm for those sal in between 2000 to 5000 while location is Ahmedabad .
SQL>select ename,dname,sal,comm from emp,dept where sal between 2000 and 5000 and loc=’AHMEDABAD’ and emp.deptno=dept.deptno;
93)Display those employees whose salary greter than his manager salary.
SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.sal>e.sal;
94) Display those employees who are working in the same dept where his manager is work.
SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.deptno=e.deptno;
95) Display those employees who are not working under any manager.
SQL>select ename from emp where mgr is null;
96) Display grade and employees name for the dept no 10 or 30 but grade is not 4 while joined the company before 31-dec-82.
SQL>select ename,grade from emp,salgrade where sal between losal and hisal and deptno in(10,30) and grade<>4 and hiredate<’31-DEC-82′;
97) Update the salary of each employee by 10% increment who are not eligiblw for commission.
SQL>update emp set sal=sal+sal*10/100 where comm is null;
98) SELECT those employee who joined the company before 31-dec-82 while their dept location is newyork or Chicago.
SQL>SELECT EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPT WHERE (EMP.DEPTNO=DEPT.DEPTNO)AND HIREDATE <’31-DEC-82′ AND DEPT.LOC IN(‘CHICAGO’,'NEW YORK’);
99) DISPLAY EMPLOYEE NAME,JOB,DEPARTMENT,LOCATION FOR ALL WHO ARE WORKING AS MANAGER?
SQL>select ename,JOB,DNAME,LOCATION from emp,DEPT where mgr is not null;
100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS AKKI? –[AND ALSO DISPLAY THEIR MANAGER NAME]?
SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR AND E.ENAME=’AKKI’;
101) Display name and salary of ford if his salary is equal to hisal of his grade
SQL>select ename,sal,grade from emp,salgrade where sal between losal and hisal and ename =’FORD’ AND HISAL=SAL;
102) Display employee name,job,depart name ,manager name,his grade and make out an under department wise?
SQL>SELECT E.ENAME,E.JOB,DNAME,EMP.ENAME,GRADE FROM EMP,EMP E,SALGRADE,DEPT WHERE EMP.SAL BETWEEN LOSAL AND HISAL AND EMP.EMPNO=E.MGR AND EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME;
103) List out all employees name,job,salary,grade and depart name for every one in the company except ‘CLERK’.Sort on salary display the highest salary?
SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE FROM EMP,SALGRADE,DEPT WHERE SAL BETWEEN LOSAL AND HISAL AND EMP.DEPTNO=DEPT.DEPTNO AND JOB NOT IN(‘CLERK’)ORDER BY SAL ASC;
104) Display the employee name,job and his manager.Display also employee who are without manager?
SQL>select e.ename,e.job,eMP.ename AS Manager from emp,emp e where emp.empno(+)=e.mgr;
105) Find out the top 5 earners of company?
SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL>=E.SAL)ORDER BY SAL DESC;
106) Display name of those employee who are getting the highest salary?
SQL>select ename from emp where sal=(select max(sal) from emp);
107) Display those employee whose salary is equal to average of maximum and minimum?
SQL>select ename from emp where sal=(select max(sal)+min(sal)/2 from emp);
108) Select count of employee in each department where count greater than 3?
SQL>select count(*) from emp group by deptno having count(deptno)>3;
109) Display dname where at least 3 are working and display only department name?
SQL>select distinct d.dname from dept d,emp e where d.deptno=e.deptno and 3>any (selectcount(deptno) from emp group by deptno);
110) Display name of those managers name whose salary is more than average salary of his company?
SQL>SELECT E.ENAME,EMP.ENAME FROM EMP,EMP E WHERE EMP.EMPNO=E.MGR AND E.SAL>(SELECT AVG(SAL) FROM EMP);
111)Display those managers name whose salary is more than average salary of his employee?
SQL>SELECT DISTINCT EMP.ENAME FROM EMP,EMP E WHERE
E.SAL <(SELECT AVG(EMP.SAL) FROM EMP
WHERE EMP.EMPNO=E.MGR GROUP BY EMP.ENAME) AND
EMP.EMPNO=E.MGR;
112) Display employee name,sal,comm and net pay for those employee whose net pay is greter than or equal to any other employee salary of the company?
SQL>select ename,sal,comm,sal+nvl(comm,0) as NetPay from emp where sal+nvl(comm,0) >any (select sal from emp);
113) Display all employees names with total sal of company with each employee name?
SQL>SELECT ENAME,(SELECT SUM(SAL) FROM EMP) FROM EMP;
114) Find out last 5(least)earners of the company.?
SQL>SELECT DISTINCT SAL FROM EMP E WHERE
5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL<=E.SAL)
ORDER BY SAL DESC;
115) Find out the number of employees whose salary is greater than their manager salary?
SQL>SELECT E.ENAME FROM EMP ,EMP E WHERE EMP.EMPNO=E.MGR AND EMP.SAL<E.SAL;
116) Display those department where no employee working?
SQL>select dname from emp,dept where emp.deptno not in(emp.deptno);
117) Display those employee whose salary is ODD value?
SQL>select * from emp where sal<0;
118) Display those employee whose salary contains alleast 3 digits?
SQL>select * from emp where length(sal)>=3;
119) Display those employee who joined in the company in the month of Dec?
SQL>select ename from emp where to_char(hiredate,’MON’)=’DEC’;
120) Display those employees whose name contains “A”?
SQL>select ename from emp where instr(ename,’A')>0;
or
SQL>select ename from emp where ename like(‘%A%’);
121) Display those employee whose deptno is available in salary?
SQL>select emp.ename from emp, emp e where emp.sal=e.deptno;
122) Display those employee whose first 2 characters from hiredate -last 2 characters of salary?
SQL>select ename,SUBSTR(hiredate,1,2)||ENAME||substr(sal,-2,2) from emp;
123) Display those employee whose 10% of salary is equal to the year of joining?
SQL>select ename from emp where to_char(hiredate,’YY’)=sal*0.1;
124) Display those employee who are working in sales or research?
SQL>SELECT ENAME FROM EMP WHERE DEPTNO IN(SELECT DEPTNO FROM DEPT WHERE DNAME IN(‘SALES’,'RESEARCH’));
125) Display the grade of Akki?
SQL>SELECT ENAME,GRADE FROM EMP,SALGRADE WHERE SAL BETWEEN LOSAL AND HISAL AND Ename=’Akki’;
126) Display those employees who joined the company before 15 of the month?
SQL>select ename from emp where to_char(hiredate,’DD’)<15;
127) Display those employee who has joined before 15th of the month.
SQL>select ename from emp where to_char(hiredate,’DD’)<15;
128) Delete those records where no of employees in a particular department is less than 3.
SQL>delete from emp where deptno=(select deptno from emp group by deptno having count(deptno)<3);
129) Display the name of the department where no employee working.
SQL> SELECT E.ENAME,E.JOB,M.ENAME,M.JOB FROM EMP E,EMP M WHERE E.MGR=M.EMPNO;
130) Display those employees who are working as manager.
SQL>SELECT M.ENAME MANAGER FROM EMP M ,EMP E WHERE E.MGR=M.EMPNO GROUP BY M.ENAME;
131) Display those employees whose grade is equal to any number of sal but not equal to first number of sal?
SQL> SELECT ENAME,GRADE FROM EMP,SALGRADE WHERE GRADE NOT IN(SELECT SUBSTR(SAL,0,1)FROM EMP);
132) Print the details of all the employees who are Sub-ordinate to BLAKE?
SQL>select emp.ename from emp, emp e where emp.mgr=e.empno and e.ename=’BLAKE’;
133) Display employee name and his salary whose salary is greater than highest average of department number?
SQL>SELECT SAL FROM EMP WHERE SAL>(SELECT MAX(AVG(SAL)) FROM EMP GROUP BY DEPTNO);
134) Display the 10th record of emp table(without using rowid)
SQL>SELECT * FROM EMP WHERE ROWNUM<11 MINUS SELECT * FROM EMP WHERE ROWNUM<10;
135) Display the half of the ename’s in upper case and remaining lowercase?
SQL>SELECT SUBSTR(LOWER(ENAME),1,3)||SUBSTR(UPPER(ENAME),3,LENGTH(ENAME)) FROM EMP;
136) Display the 10th record of emp table without using group by and rowid?
SQL>SELECT * FROM EMP WHERE ROWNUM<11 MINUS SELECT * FROM EMP WHERE ROWNUM<10;
137) Create a copy of emp table;
SQL>create table new_table as select * from emp where 1=2;
138) Select ename if ename exists more than once.
SQL>select ename from emp e group by ename having count(*)>1;
139) Display all enames in reverse order?(SMITH:HTIMS).
SQL>SELECT REVERSE(ENAME)FROM EMP;
140) Display those employee whose joining of month and grade is equal.
SQL>SELECT ENAME FROM EMP WHERE SAL BETWEEN
(SELECT LOSAL FROM SALGRADE WHERE
GRADE=TO_CHAR(HIREDATE,’MM’)) AND
(SELECT HISAL FROM SALGRADE WHERE
GRADE=TO_CHAR(HIREDATE,’MM’));
141) Display those employee whose joining DATE is available in deptno.
SQL>SELECT ENAME FROM EMP WHERE TO_CHAR(HIREDATE,’DD’)=DEPTNO;
142) Display those employees name as follows
A ALLEN
B BLAKE
SQL> SELECT SUBSTR(ENAME,1,1),ENAME FROM EMP;
143) List out the employees ename,sal,PF(20% OF SAL) from emp;
SQL>SELECT ENAME,SAL,SAL*.2 AS PF FROM EMP;
144) Create table emp with only one column empno;
SQL>Create table emp as select empno from emp where 1=2;
145) Add this column to emp table ename vrachar2(20).
SQL>alter table emp add(ename varchar2(20));
146) Oops I forgot give the primary key constraint. Add in now.
SQL>alter table emp add primary key(empno);
147) Now increase the length of ename column to 30 characters.
SQL>alter table emp modify(ename varchar2(30));
148) Add salary column to emp table.
SQL>alter table emp add(sal number(10));
149) I want to give a validation saying that salary cannot be greater 10,000 (note give a name to this constraint)
SQL>alter table emp add constraint chk_001 check(sal<=10000);
150) For the time being I have decided that I will not impose this validation.My boss has agreed to pay more than 10,000.
SQL>again alter the table or drop constraint with alter table emp drop constraint chk_001 (or)Disable the constraint by using alter table emp modify constraint chk_001 disable;
151) My boss has changed his mind. Now he doesn’t want to pay more than 10,000.so revoke that salary constraint.
SQL>alter table emp modify constraint chk_001 enable;
152) Add column called as mgr to your emp table;
SQL>alter table emp add(mgr number(5));
153) Oh! This column should be related to empno. Give a command to add this constraint.
SQL>ALTER TABLE EMP ADD CONSTRAINT MGR_DEPT FOREIGN KEY(MGR) REFERENCESEMP(EMPNO);
154) Add deptno column to your emp table;
SQL>alter table emp add(deptno number(5));
155) This deptno column should be related to deptno column of dept table;
SQL>alter table emp add constraint dept_001 foreign key(deptno) reference dept(deptno) [deptno should be primary key];
156) Give the command to add the constraint.
SQL>alter table <table_name) add constraint <constraint_name> <constraint type>;
157) Create table called as newemp. Using single command create this table as well as get data into this table(use create table as);
SQL>create table newemp as select * from emp;
SQL>Create table called as newemp. This table should contain only
empno,ename,dname.
SQL>create table newemp as select empno,ename,dname from emp,dept where
1=2;
158) Delete the rows of employees who are working in the company for more than 2 years.
SQL>delete from emp where (sysdate-hiredate)/365>2;
159) Provide a commission(10% Comm Of Sal) to employees who are not earning any commission.
SQL>select sal*0.1 from emp where comm is null;
160) If any employee has commission his commission should be incremented by 10% of his salary.
SQL>update emp set comm=sal*.1 where comm is not null;
161) Display employee name and department name for each employee.
SQL>select empno,dname from emp,dept where emp.deptno=dept.deptno;
162)Display employee number,name and location of the department in which he is working.
SQL>select empno,ename,loc,dname from emp,dept where emp.deptno=dept.deptno;
163) Display ename,dname even if there are no employees working in a particular department(use outer join).
SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno(+);
164) Display employee name and his manager name.
SQL>select p.ename,e.ename from emp e,emp p where e.empno=p.mgr;
165) Display the department name and total number of employees in each department.
SQL>select dname,count(ename) from emp,dept where emp.deptno=dept.deptno group by dname;
166)Display the department name along with total salary in each department.
SQL>select dname,sum(sal) from emp,dept where emp.deptno=dept.deptno group by dname;
167) Display itemname and total sales amount for each item.
SQL>select itemname,sum(amount) from item group by itemname;
168) Write a Query To Delete The Repeted Rows from emp table;
SQL>Delete from emp where rowid not in(select min(rowid)from emp group by ename);
169) TO DISPLAY 5 TO 7 ROWS FROM A TABLE
SQL>select ename from emp where rowid in(select rowid from emp where rownum<=7 minusselect rowid from empi where rownum<5);
170) DISPLAY TOP N ROWS FROM TABLE?
SQL>SELECT * FROM
(SELECT * FROM EMP ORDER BY ENAME DESC)
WHERE ROWNUM <10;
171) DISPLAY TOP 3 SALARIES FROM EMP;
SQL>SELECT SAL FROM ( SELECT * FROM EMP ORDER BY SAL DESC ) WHERE ROWNUM <4;
172) DISPLAY 9th FROM THE EMP TABLE?
SQL>SELECT ENAME FROM EMP
WHERE ROWID=(SELECT ROWID FROM EMP WHERE ROWNUM<=10
MINUS
SELECT ROWID FROM EMP WHERE ROWNUM <10);
173) select second max salary from emp
select max(sal) fromemp where sal<(select max(sal) from emp);
174) Delete the 10th record of emp table.
SQL>DELETE FROM EMP WHERE EMPNO=(SELECT EMPNO FROM EMP WHERE ROWNUM<11 MINUS
SELECT EMPNO FROM EMP WHERE ROWNUM<10);
