posted Feb 23, 2012, 7:50 AM by Neil Mathew
[
updated Feb 23, 2012, 8:11 AM
]
SOURCE CODE:
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| #include<iostream.h>
#include<conio.h>
#include<graphics.h>
int n;
int P[3][10];
int P2[3][10];
int T[3][3];
int tx,ty;
void INPUT()
{
cout<<"\n For Polygon where No of edges (>3) = ";
cin>>n;
cout<<"\n Enter the coordinates of "<<n<<" sided Polygon: \n";
for(int i=0; i<n; i++)
{
cout<<" "<<i+1<<" Point (x,y) : ";
cin>>P[0][i]>>P[1][i];
P[2][i]=1;
}
cout<<"\n Enter the Translation Factors:";
cout<<"\n for X axis: "; cin>>tx;
cout<<" for Y axis: "; cin>>ty;
}
void Translate()
{
// T[3][3] : Translation MATRIX
// P[3][n] : 3 x n MATRIX
// P2[3][n] : Final MATRIX
//Transaction Matrix:
//1st - making the identity Matrix
for(int i=0; i<3; i++)
{
for(int j=0; j<3; j++)
{
if(i==j) //DIAGONAL
T[i][j] = 1;
else
T[i][j] = 0;
}
}
//2nd - making changes
T[0][2] = tx;
T[1][2] = ty;
// Matrix Multiplication
// T(3x3) x P(3xN)
for(i=0; i<3; i++)
{
for(int j=0; j<n; j++)
{
P2[i][j]=0;
for(int k=0; k<3; k++)
{
P2[i][j]+=T[i][k]*P[k][j];
}
}
}
}
void Display_Matrix(int p[3][10])
{
for(int i=0; i<3; i++)
{
cout<<"\n |";
for(int j=0; j<n; j++)
cout<<" "<<p[i][j];
cout<<" |";
}
}
void DRAW(int p[3][10])
{
for(int i=0; i<n-1; i++)
{
line(p[0][i], p[1][i], p[0][i+1], p[1][i+1]);
}
line(p[0][n-1], p[1][n-1], p[0][0], p[1][0]);
}
void main()
{
INPUT();
Display_Matrix(P);
cout<<endl;
Translate();
for(int i=0; i<3; i++)
{
cout<<"\n |";
for(int j=0; j<3; j++)
cout<<" "<<T[i][j];
cout<<" |";
}
cout<<endl;
Display_Matrix(P2);
cout<<"\n\n Press Enter to see Graphically? ";
getch();
int gdriver=DETECT,gmode;
initgraph(&gdriver,&gmode,"C:/TC/BGI");
setcolor(CYAN);
DRAW(P);
setcolor(GREEN);
DRAW(P2);
getch();
closegraph();
} |
OUTPUT:
|
|